help me out here!!!
#22
RE: help me out here!!!
ORIGINAL: veloracer
The length of the rope would be 0.75m... same as the radius
ORIGINAL: AWDaholic
^^that assumes the rope is taut, which isn't stated. 3/4 meter could be with teh weight only circling at 1/2 speed, or full speed. We don't know. The radius is given, but not teh lenght of the rope.
^^that assumes the rope is taut, which isn't stated. 3/4 meter could be with teh weight only circling at 1/2 speed, or full speed. We don't know. The radius is given, but not teh lenght of the rope.
You should go Audi-slap (ahem: If your PIMP-hand is Audi-STRONG, you will never hafta raise it) your instructor for not being explicit enough in providing FULL disclosure in his/her equations
#24
RE: help me out here!!!
ORIGINAL: marko_tomas13
You're usually assuming the rope is taught with these problems.
You also assume ropes are massless, you can't push with a rope, and that they don't flex or twist.
ORIGINAL: AWDaholic
^^that assumes the rope is taut, which isn't stated. 3/4 meter could be with teh weight only circling at 1/2 speed, or full speed. We don't know. The radius is given, but not teh lenght of the rope.
^^that assumes the rope is taut, which isn't stated. 3/4 meter could be with teh weight only circling at 1/2 speed, or full speed. We don't know. The radius is given, but not teh lenght of the rope.
You also assume ropes are massless, you can't push with a rope, and that they don't flex or twist.
ahem: ANSWER = 12
massless or not, you CAN push a rope. Oh, it'll clump up on you, but, I can *push* a pile of rope as easily as I can push a pile of steeming poo.
if I need to push a rope at FULL extension, I can also add in an assumption that the ambient temprature is -100c, which should freeze most rope. of course, you could counter with an assumption that the rope is 1-mile thick, which means I'll need to drop the temprature assumption considerably to freeze it stiff, OR, assume teh rops is made of merangue, which, may or may not freeze solid at -100c & 1-mile thick...
If you want a precise answer give me PRECISE PARAMETERS
#25
RE: help me out here!!!
lol, i didnt know people were actually going to try to help me out. i knew the answers, i was just lettingyou have some quality fun!! yes the rope fully extended and taut is .75 m. its alot easier to understand whenyou are looking at the little diagram, i couldnt get it on the computer.
no, you do notneed to know time, the equation for the first one is w= change in theta/theda over change in time which in rotation is1 sec. dont ask quesitions,just accept that it is 1 sec, i assume that is to be expected. the second equation is w*r=Vt and i dont remember the third on because finals are over!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!
thank you everyone
no, you do notneed to know time, the equation for the first one is w= change in theta/theda over change in time which in rotation is1 sec. dont ask quesitions,just accept that it is 1 sec, i assume that is to be expected. the second equation is w*r=Vt and i dont remember the third on because finals are over!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!
thank you everyone
#27
RE: help me out here!!!
ORIGINAL: scotts custom
lol, i didnt know people were actually going to try to help me out. i knew the answers, i was just lettingyou have some quality fun!! yes the rope fully extended and taut is .75 m. its alot easier to understand whenyou are looking at the little diagram, i couldnt get it on the computer.
no, you do notneed to know time, the equation for the first one is w= change in theta/theda over change in time which in rotation is1 sec. dont ask quesitions,just accept that it is 1 sec, i assume that is to be expected. the second equation is w*r=Vt and i dont remember the third on because finals are over!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!
thank you everyone
lol, i didnt know people were actually going to try to help me out. i knew the answers, i was just lettingyou have some quality fun!! yes the rope fully extended and taut is .75 m. its alot easier to understand whenyou are looking at the little diagram, i couldnt get it on the computer.
no, you do notneed to know time, the equation for the first one is w= change in theta/theda over change in time which in rotation is1 sec. dont ask quesitions,just accept that it is 1 sec, i assume that is to be expected. the second equation is w*r=Vt and i dont remember the third on because finals are over!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!
thank you everyone
That question seems odd. Are you sure they weren't asking for answers expressed without #'s... like leaving a T value in there, and just showing HOW it'd be solved? Weird stuff.
Anyhow, my finals are over too. Wooo!